Calculus I, BTrack 
Test #1

September 30, 2002

Name____________________ 
R. Hammack

Score ______

(1) (10 points)
(a)
(b) Find all the x values that are not in the domain
of the function .
The denominator will be zero for those values of x for which sin(x)
=1/2.
Therefore the values x =
and x =
(where n is an integer) are not in the domain of f.
(2) (10 points)
(a) Sketch the graph of the equation .
To find the xintercept, set y = 0 and solve for x. You
get x = 2.
To find the yintercept, set x = 0 and solve for y. You
get y = 4.
(3) (10 points) Consider the functions and
(a)
(b)
(4) (20 points) Evaluate the following limits.
(a)
(b) 0
(c) (0)(1) = 0
(d)
(5) (35 points) This problem concerns the function .
(a) State the domain of f.
Observe =(provided x is neither 0 nor 2)
Note that x = 0 or x = 2 will give a zero in the denominator, so these values are not in the domain. However, any other value of x will work. Therefore the domain of f is all real numbers except 0 and 2.
(b) (2+2)/2 = 2
(c) (Note highest power of x occcurs on both top and bottom, each with coefficient 1.)
(d) (Note, top gets closer to 2, and bottom gets closer to 0, but positive.)
(e)
(f) List the vertical asymptote(s) of f (if any). (Feel free to use any relevant information from parts ad above)
By part, (d), the line x=0 is a vertical asynptote,
(g) List the horizontal asymptote(s) of f (if any). (Feel free to use any relevant information from parts ad above)
By part, (c), the line y=1 is a horizontal asynptote,
(6) (10 points) This problem concerns the function
(a)
(b)
(c)
(d) D.N.E. because right and lefthand limits do not agree.
(e) Is f continuous at x = 0? (Explain, using above information.)
NO, because does not exist, so it's impossible that
(f)
(g)
(h)
(i) 0, by parts g and h above
(j) Is f continuous at x = 1? (Explain, using above information.)
YES, because the above shows
(7) (5 points) Sketch the graph of a function f satisfying the following properties: , , , , and , There are many correct answers.